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Solving the 1D Heat Equation with a Non-homogeneous Source Using Separation of Variables and Laplace Transforms

January 07, 2025Technology1251
Solving the 1D Heat Equation with a No

Solving the 1D Heat Equation with a Non-homogeneous Source Using Separation of Variables and Laplace Transforms

The 1D Heat Equation is a fundamental partial differential equation (PDE) that models how heat distributes through a body over time. In this article, we will explore how to solve the 1D Heat Equation with a non-homogeneous external heat source using two common methods: separation of variables and Laplace transforms.

The 1D Heat Equation with an External Heat Source

The 1D Heat Equation with an external heat source can be represented by the following equation:

[ frac{partial u}{partial t} - a^2 frac{partial^2 u}{partial x^2} 1 ]

This equation models an insulated thin metal rod where the temperature changes over time and is influenced by an external heat source. The source term on the right-hand side is ( 1 ), indicating a constant external heat source.

Solution Using Separation of Variables

One method to solve this equation is by using separation of variables. Let's assume a solution of the form:

[ U(x, t) t cdot F(x) cdot G(t) ]

Substituting this into the 1D Heat Equation:

[ frac{partial (t cdot F(x) cdot G(t))}{partial t} - a^2 frac{partial^2 (t cdot F(x) cdot G(t))}{partial x^2} 1 ]

This simplifies to:

[ t cdot F(x) cdot G'(t) - a^2 cdot t cdot F''(x) cdot G(t) 1 ]

Dividing through by ( t cdot F(x) cdot G(t) ) gives:

[ frac{G'(t)}{G(t)} - a^2 frac{F''(x)}{F(x)} frac{1}{t cdot F(x) cdot G(t)} ]

For this equation to be true for all ( x ) and ( t ), we must set the left side to a constant:

[ frac{G'(t)}{G(t)} K ] and [ -a^2 frac{F''(x)}{F(x)} K ]

Where ( K ) is a constant of separation. Solving these ordinary differential equations:

[ frac{G'(t)}{G(t)} K ] gives [ G(t) C e^{Kt} ]

[ -a^2 frac{F''(x)}{F(x)} K ] gives the characteristic equation:

[ m^2 frac{K}{a^2} 0 ]

With roots:

[ m pm i frac{sqrt{K}}{a} ]

For the case ( K 0 ), we have:

[ F(x) b cx ]

Thus, the solution is:

[ U(x, t) t cdot (b cx) cdot e^{Kt} ]

For the case ( K eq 0 ), the function ( F(x) ) can be a combination of exponentials or trigonometric functions.

Solution Using Laplace Transforms

Another method is to use Laplace transforms. Consider the equation:

[ frac{partial u}{partial t} - a^2 frac{partial^2 u}{partial x^2} 1 ]

Applying the Laplace transform with respect to ( t ), we get:

[ [sU(x, s) - u(x, 0)] - a^2 frac{d^2 U}{dx^2} frac{1}{s} ]

This is a linear second-order ODE in ( U(x, s) ). After solving this, we find the inverse Laplace transform to obtain the solution:

[ u(x, t) mathcal{L}^{-1}{U(x, s)} ]

This method is particularly useful for problems with non-homogeneous source terms, boundary conditions, or initial conditions.

Conclusion

The 1D Heat Equation with a non-homogeneous external heat source can be solved using both separation of variables and Laplace transforms. Each method offers unique advantages depending on the specific problem at hand. Whether you are dealing with an insulated thin metal rod or other heat transfer problems, understanding these methods can greatly enhance your ability to find solutions accurately and efficiently.

Keywords

Heat Equation Separation of Variables Laplace Transforms