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Finding the MLE of the Standard Deviation of the Poisson Distribution
How to Find the Maximum Likelihood Estimator (MLE) of the Standard Deviation in a Poisson Distribution
Understanding the Maximum Likelihood Estimator (MLE) for the standard deviation of a Poisson distribution can seem daunting, especially when dealing with an unknown mean. In this article, we will walk through the process step-by-step, from the basics of the Poisson distribution to the derivation of the MLE for the standard deviation. We'll also explore the likelihood and log-likelihood functions to help you grasp the concept more effectively.
Poisson Distribution Basics
The Poisson distribution is a discrete probability distribution that expresses the probability of a given number of events occurring in a fixed interval of time or space. It is characterized by a single parameter, the mean (λ), denoted as lambda:
If X follows a Poisson distribution with mean λ, then the probability mass function is given by:
P(Xx)λxx!e-λwhere x 0, 1, 2, ...
Standard Deviation of a Poisson Distribution
For a Poisson distribution, the mean (λ) is equal to the variance. Consequently, the standard deviation (σ) is the square root of the mean:
σλ
Steps to Find the MLE of the Mean (λ)
To find the MLE of the mean (λ), given a random sample X1, X2, ..., Xn drawn from a Poisson distribution, follow these steps:
Likelihood Function
The likelihood function L λ for the sample is the product of the individual probabilities. For a sample of X1, X2, ..., Xn, the likelihood function is:
Lλ∏i1nPX_ix_i∏i1nλ^x_ie-x_i!
This can be simplified to:
Lλλ∑i1nx_i∏i1nx_i!e-nλ
Log-Likelihood Function
To simplify the maximization process, we take the natural logarithm of the likelihood function to obtain the log-likelihood. This is done as follows:
logLλ∑i1nlog(λ^x_ie-x_i!)∑i1nx_ilogλ-λ-logx_i!
This can be further simplified to:
logLλ(∑i1nx_i)logλ-nλ-∑i1nlogx_i!
Differentiation of the Log-Likelihood Function
Next, we differentiate the log-likelihood function with respect to λ and set the derivative equal to zero to find the MLE of λ:
?logLλ?λ∑i1nx_iλ-n0
Upon rearrangement, we get:
λ∑i1nx_in
Thus, the MLE of λ is:
λhX_1n∑i1nX_i
MLE of the Standard Deviation
Since the standard deviation (σ) is related to λ by:
σλ
We can find the MLE for the standard deviation as follows:
σhλhX_
Conclusion
In conclusion, the MLE of the standard deviation of a Poisson distribution with an unknown mean, based on a random sample, is:
σhX_1n∑i1nX_i
This method provides a systematic way to estimate the standard deviation using your sample data. If you have any further questions or need clarification on any steps, feel free to ask!
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